## How To Calculate Quantities Of Materials For Concrete

## Calculation Of Materials For Different Mix Ratio:

Quantity estimation of materials is essentially required in any construction works and quantity of materials depend on the mix proportions of the concrete. In our previous article, we have already discussed **how to calculate bricks in a wall.** Today we will discuss how to calculate quantities of materials for different mix ratio of concrete. (Dry mix method)

We will calculate quantities of materials for 1 m3 concrete (By volume).

Let us assume the mix proportion is 1 : 2: 4 (cement:sand:stone =a:b:c)

Volume of wet concrete = 1 m3

Volume of dry concrete = 1 Ã— 1.54 = 1.54 m3

**What Is 1.54 Given Below:**

Or You Can check out this article – **What is 1.54 in Concrete Calculation.**

## Calculation For Cement:

Formula, Cement = (Volume of dry concrete/a+b+c) Ã— a

= (1.54/a+b+c) Ã— a = [(1.54/1+2+4)] Ã— 1 = 0.22 cum

Now density of cement = 1440 kg/cum

âˆ´ Volume of cement = 0.22 Ã— 1440 =316.8 kg.

As we know, 1 bag of cement contains 50 kg of cement .

âˆ´ Cement bags required = 316.8/50 = 6.33 bags.

## Calculation For Sand:

Formula, Sand = (Volume of dry concrete/a+b+c) Ã— b

= (1.54/a+b+c) Ã— b = (1.54/1+2+4) Ã— 2 = 0.44 cum.

## Calculation For Aggregates:

Formula, Stone Chips = (Volume of dry concrete/a+b+c) Ã— c

= (1.54/a+b+c) Ã—c = (1.54/1+2+4) Ã— 4 = 0.88 cum.

## Calculation For Water Content:

Let us assume the water/cement ratio of the concrete is 0.45.

w/c = 0.45

Required water for 1 bag cement = 0.45 Ã— 0.0353 = 0.0159 cum.

Where volume of 50 kg cement = 0.0353 cum

1 m3 water = 1000 Litre

Required water for 1 bag cement=0.0159 Ã— 1000 = 15.9 Litre.

âˆ´ Required water for 6.33 bags cement = 6.33 Ã— 15.9 = 101 Litre.

## Summary:

Cement = 6.33 bags.

Sand = 0.44 cum

Aggregates = 0.88 cum

Water = 101 litre.

**Note: **Yield of concrete is considered as 67% &

Wastages of materials = 2%

You can use the same formula for different mix proportions such as 1:1.5:3 etc.

Here, we have used cubic meter unit but you can also calculate in cubic feet unit.

##### Also** Read – Concrete Mix** Design.

## Comments ( 62 )

why we multiply wet concrete by 1.54

this was very useful… thanking u

I have explained, What is 1.54. Now you can check it in the article.

It’s dry volume of concrete. We multiply 1.54 due to voids present in it.

Due to content of water in dry material automatically dry material reduces to 50 to 55 percent so we add it 54 percent in to dry material.

Absolutely awesome thx Guys

plaster 12 mm thik for ratio 1:6

Proses send me

What is the density of sand and aggregate

It’s was the dry volume denisty fix value

Thank you for your kind sharing. As a guideline, please advise on the nominal mix proportion by Volume for M40 would be 1 : ??? : ???

The approximate quantities are

Cement = ??? bags/cum of concrete

Sand = ??? cft/cum

Aggregate = ??? cft/cum Your kind sharing is very much appreciated

Thank you so much much for the detailed information

Sir articles are very good. Please provide articles related to tender

Sir can you explain why we multiply wet concrete by 1.54.

its the matter of dry wt and wet wt

Im no engnr wanted to lessen my expenses to renovate my house can you please help me …. Thank you so much

Vry useful

What is cft

cft means Cubic-Feet.

Cubic feet

We take volume 10 cum not 100cuf for rcc and pcc

Or which unit is preferable feet or meter

thanks for given details information

Very useful it

What is 1.54

Please explain

Explained, What is 1.54. You can check it in the article.

good

why we multiply wet concrete by 1.54?

why we multiply wet concrete by 1.54

I have explained, What is 1.54. Now you can check it in the article.

Very usefull info

It is useful in civil engineering works

Thanks to useful formula provided

How to defined 1.54

How can be calculate water content . And where the 0.0353 and 0.45 value can be taken .please describe me

.45 is water/cement proportion and .035m3 is the vol. Of cement bag

54percent ye samajh nahi aya. .

Nice informations

Such valuable information about taking quantities on concrete, it has more than enough Detailing.

thanks

Sir wht is 1.54 explain plz

1.54 mean, volume + shrinkage of concrete= 1 + 54%

1.54 mean, volume + shrinkage of concrete= 1 + 54%

sir, it is very useful information But sir i have one dout plz clear this what is 0.0353 in water

Volume of 50kg cement bag

Please Explained, what is 0.0353 in water?

It’s okay, but I need also culculation of sand, cement and stones required in stone pitching

What is .0352 sir please clear

volume of cement=mass/density…(50kg/1440kg/m3)=0.0347cum

Vry nice correct answer

Wonderful practice calculations. Keep it up

In Note you have written “Yield of concrete is considered as 67%” what does that actually mean? Please elaborate.

How to find aggregate and sand in Kg it is given in cum??

sir please explain what is 0.353 which you multiply with 0.45 in calculation of water content .. please i need the answer will be very thankfull to you

What if we have to calculate for different dimension like for L=5m, B=3m, T=1m, then? How to calculate??

dear sir, thank you so much for this information, please upload how to calculate no of footing and coloumn in a roof slab??

Please where do you get 1440kg/m3 from? And what’s meant by cum?

How to calculate/use sand and aggregate in site , which is in cubic feet or cubic meter

Thank you very much for this kind of articles.Its really useful .Thank you very much again.

It is a nice crystal clear article,and very useful, thanks,

How can be calculate the RCC Concrete

You can calculate the total volume of stone required through using the formula given below:

length x width x height = volume in cubic feet

However, it could be quite difficult for a non-professional to calculate the total volume, therefore it would be best to hire a professional Brick & Stone Repointing service provider to do the job for you.

Pls I need Box culvert analysis

Thank you for your kind sharing. As a guideline, please advise on the nominal mix proportion by Volume for M40 would be 1 : ??? : ???

The approximate quantities are

Cement = ??? bags/cum of concrete

Sand = ??? cft/cum

Aggregate = ??? cft/cum Your kind sharing is very much appreciated

Thank you so much, this was a very useful material.