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Quantity Of Cement & Sand Required For 100 Sq.ft Plastering Work

Quantity Of Cement & Sand Required For 100 Sq.ft Plastering Work:

Plastering is one of the most important work needs to be done to protect the surface of wall or roof ceiling. In this article I will discuss quantity of cement and sand required for 100  sq.ft plastering wall (12 mm thickness). After that you will be able to calculate as per your desired area.


To make my calculation easier I will convert feet unit in meter unit.

Area of plaster = 100 sq.ft = 9.29 m²

Thickness of plaster = 12 mm = 0.012 m

Mix ratio of plaster = cement : sand = 1: 4

Volume of plaster = Area of plaster x Thickness of plaster = 9.29 x 0.012 = 0.11 m³

Now we need to add extra 20% for joint filling, depression and wastage.

Volume of plaster = 0.11 b+ (20×0.11/100) = 0.13 m³

This is wet volume, we need find out dry volume. To get dry volume multiply wet volume with 1.35

∴ Dry volume = wet volume x 1.35 = 0.17 m³

Quantity Of Cement:

Cement = ( Dry vol of plaster x cement ratio)/ Total sum of ratio

= 0.17 x 1/5 = 0.03 m³

We know density of cement = 1440kg/m³

∴ Weight of cement = 0.03 x 1440 = 48.96 = 50 kg

1 bag cement contains 50 kg of cement.

Quantity Of Sand:

Sand = Quantity of cement x 4 = 0.03 x4 = 0.12 m³

1 m3 = 35.3147 cubic feet = or cft

∴ Sand required = 0.12 x 35.3147 = 4.23 cft

Summery:

Cement Required =  1 bag

Sand required = 4.23 cft



Comments ( 5 )

  1. 0.17 dry volume how to come
    quantity cement 0.03 cum but find in quantity sand qut cement 0.3cum how to come

  2. Mohammad Hassan Alami
    March 1, 2019 at 12:57 pm

    Very Best Engineering information

  3. Very gud way of teaching.

  4. Quantity of sand is incorrect, as qty of cement is taken 0.3 but it’s 0.03

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