How To Calculate Brick, Cement And Sand In Brick Masonry

Quantity estimation of materials is essentially required in any construction works and the quantity of materials depends on the mix proportions of the concrete. In this article, I will discuss how to calculate bricks, cement, and sand in brick masonry. So let’s get started.

Assuming,

1. Volume of brickwork = 1 m³
2. Grade of mortar = 1:6 (cement : sand)
3. First class brick (190 mm x 90 mm x 90 mm)
4. Thickness of mortar = 10 mm = 0.01 m

No. Of Bricks:

No. of bricks = (Volume of brickwork / Volume of one brick with mortar)

Volume of one brick without mortar = 0.19×0.09×0.09 = 0.001539 m³

Volume of brick with mortar = (0.19+0.01) x (0.09+0.1)x (0.09+0.1)

= 0.2×0.1×0.1 = 0.002 m³

No.of bricks = 1.0/ (0.002) = 500

Consider 10% to 15 % bricks as wastage.

∴ Total no. of bricks = 500 + (10 x 500 )/100 = 550

Quantity Of Mortar:

Volume occupied by bricks = No. of bricks x Volume of one brick

Volume of bricks = 500 x 0.001539 = 0.7695 m³

Volume of mortar = Volume of brickwork – Volume of bricks

∴ Volume of Mortar = 1.0 – 0.7695 = 0.2305 m³

Quantity Of Cement:

Cement = (Dry volume of mortar x Cement ratio)/ Sum of the ratio

Dry volume of Mortar = 1.54 x 0.2305 = 0.35497 m³ (54% increment due to volume shrink after adding water)

Cement= (0.35497 x 1) / (1+6) = 0.35497/7= 0.05071 m³

Cement = 0.043795 x 1440 = 73.0224 kg

∴ No. of cement bags = 73.0224 / 50 = 1.45 bags (1 bag cement contains 50 kg cement)

Quantity of Sand:

Sand = (Dry volume of mortar x Sand ratio)/Sum of the ratio

Sand = (0.35497 x 6)/7 = 2.12982/7 = 0.30426 m³

∴ Sand = 0.30426 x 35.3147 = 10.7448 cft.

Summery:

Number of Bricks = 550

Cement = 1.45 bags of 50 Kg

Sand = 0.30426 m³ or10.7448 cft.