Quantity of Brick, Cement, Sand And Aggregates Required To Build 10ft x 10ft Room

Before calculating the number of bricks and quantity of concrete, we need to know some data. Let us assume

The length of room = 10 ft

breadth of room = 10 ft

Height of room = 10 ft.

For easier calculation we will use M15 grade concrete. For M15 concrete

Cement : Sand : Aggregates = 1:2:4

Calculation For Floor And Ceilings:

Volume of floor/ceiling = 10x10x1 (assuming thickness of slab =1ft)= 100 cft

1 bag of cement contains 50 kg cement = 1.71cft

For M15 concrete (1:2:4),

Sand required for 1 bag cement = 1.71 x 2 = 3.42 cft

Aggregates required for 1 bag cement = 1.71 x 4v = 6.84 cft

Total Volume = Cement+Sand+Aggregates = 1.71 + 3.42 + 6.84 = 11.97 cft

Cement required for 100 cft volume = (100/11.97) x 1.71 = 14.19 cft

Sand required for 100 cft volume = (100/11.97) x 3.42 = 28.38 cft

Aggregates for 100 cft volume = (100/11.97) x 6.84 = 56.76 cft

For ceiling, the abouve quantity will be doubled.

Calculation For Walls:

Assuming load bearing structure (ignoring beams and columns) assume 20% of floor area is required for openings (door, windows, ventilation).

Openings need to be provided = 20sq.ft

Thickness of wall = 9 inch

Rough volume of wall = [ (9In x 9In x 4) + (8.5ft x 9In x 4) ] x 10 ft = 257.25 cuft

Opening subtractions = 257.25 – 20% of 257.25 = 205.8 cuft

Volume of one Brick = 0.24 ft x 0.37 ft x 0.75 ft = 0.06 cuft

Total no. of bricks = 205.8 cuft / 0.06 cuft = 3430 Bricks

Mortar to be applied on bottom and one end of brick. Volume of mortar for 1 brick = (0.24 x 0.75 x 0.03) + (0.75 x 0.37 x 0.03) = 0.013 cuft.

Total number of bricks = 3430; Thus total Mortar required = 3430 x 0.013 = 44.59 cuft; Mortar ratio normally used = 1 : 5 ( Cement : Sand ); Thus total Cement = 11.84 cuft; Total Sand = 32.75 cuft.

Now For the Final Calculations, The total material required is –

a. Cement = 14.19 x 2 + 11.84 = 40.22 cuft Or 1.14 cum; (Density of cement is 1440 kg/cum); Thus, Mass = 1,641.6 Kg or 33 bags of 50 Kg.

b. Sand = 28.38 x 2 + 32.75 = 117.89 cuft Or 3.3 cum; (Density of sand is 1350 kg/cum); Thus, Mass = 1,455 Kg or 90 Bags of 50 Kg.

c. Coarse Aggregate = 56.72 x 2 = 113.44 cuft Or 1.6 cum; (Density of coarse aggregate is 1300 kg/cum); Thus, Mass = 2,080 Kg or 42 bags of 50 Kg.

d. Bricks = 3,430 Bricks.